Gate 4 - Product Explanation and Reassembly - Group 6 2012
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*The rotor is connected to the hammer and spins due to the force exerted by the compressed air on the fins. The spinning completes the conversion of the potential energy of the compressed air into mechanical energy and finally the torque output. | *The rotor is connected to the hammer and spins due to the force exerted by the compressed air on the fins. The spinning completes the conversion of the potential energy of the compressed air into mechanical energy and finally the torque output. | ||
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| + | ! scope="col"| Part | ||
| + | ! scope="col"| Assumptions | ||
| + | ! scope="col"| Equations | ||
| + | ! scope="col"| Explanation | ||
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| + | '''Fins''' | ||
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| + | *Mass is constant | ||
| + | *Fins are uniform in shape and size and density is constant | ||
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| + | '''Pressure Defined:''' | ||
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| + | PA=F '''(2)''' | ||
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| + | '''Impulse (a relationship defined by Newton’s Second Law):''' | ||
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| + | J=∫Fdt = ∆p = m∆v '''(6a)''' | ||
| + | |||
| + | where J is an impulse, ∫_∆tFdt is the integral of the force F over an interval of time t, ∆p is the change in momentum, m is the mass, and ∆v is the change in velocity | ||
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| + | The force exerted on the fins by the compressed air is a function of the pressure of the compressed air and the surface area of the fins. There is a direct relationship between the surface area of the fins and the force on the fins, and there is also a direct relationship between the pressure created by the air and the force exerted on the fins. | ||
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| + | When air enters the rotor chamber it incurs a change in momentum caused by the contact with the initially stationary surface of the fins. This change in momentum is transferred to the fins as an impulse, which causes an increase in velocity of the fins and thus the rotation of the rotor. | ||
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| + | '''Rotor''' | ||
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| + | *Mass is constant | ||
| + | *The rotor is of uniform density and contact within individual grooves between the rotor surface and the fins is uniform | ||
| + | *The linear momentum of each of the fins is conserved and transferred to the rotor at a single point of contact that is uniform for each fin | ||
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| + | '''Newton’s Second Law:''' | ||
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| + | F=dp/dt=d(mv)/dt=m dv/dt=ma '''(6b)''' | ||
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| + | where F is the force, and dp/dt is the rate of change of its linear momentum (p) with respect to time (t) and d(mv)/dt, the rate of change of the mass (m) times the velocity (v) with respect to time; m is brought out as a constant under the assumption of constant mass and dv/dt becomes acceleration, a | ||
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| + | '''Torque as the Time Derivative of Angular Momentum:''' | ||
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| + | τ=dL/dt=dr/dt×p+r×dp/dt=r×F '''(7)''' | ||
| + | |||
| + | where τ is torque, dL/dt is the rate of change of angular momentum with respect to time, dr/dt is the rate of change of the position vector (r) of the point relative to the center, and × indicates a cross product | ||
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| + | The force of the fins against the surface of the grooves in the rotor causes the rotor to accelerate. | ||
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| + | Due to the conservation of linear momentum, the linear momentum of the fins created by the impulse from the contact with the compressed air is transferred to the rotor at points of distance r from the rotor’s central axis. The change in linear momentum at these points on the rotor’s grooves, now a change in angular momentum given the cylindrical shape of the rotor, then creates torque. The torque spins the rotor which, in turn, spins the hammer. | ||
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'''Mechanism: Trigger''' | '''Mechanism: Trigger''' | ||
Revision as of 20:23, 29 November 2012
Click here to return to the main page for Group 6.
Contents |
Gate Introduction
This gate has several parts. The first part is project management. This section discusses the roles of each member and challenges faced. The next section is the reassembly, where videos of the wrench being reassembled are shown and the process is described. There is a section that describes the mechanisms used in the impact wrench and finally a section with three design revisions on the system level.
Project Management
This section is a table of what changes group members had to make to have the gate progress.
Critical Project Review
| Management Roles | Goals | Successes | Challenges and Resolution |
|---|---|---|---|
| Communication Liaison |
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| Project Manager and Intra-Group Communications Coordinator |
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| Technical Expert: Communications Technology |
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| Technical Experts: Dis-assembly Technicians |
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Product Reassembly
Mechanisms
This section overviews the mechanisms that are present in the impact wrench.
Mechanism: Plunger/Back Plate and Switch
The plunger acts as a gate valve, connecting the user interface (back plate) with the control of the air flow to the rotor mechanism.
- The plunger is connected to a switch on the back plate which allows the user to rotate the plunger. It is an obstruction inside of the valve sleeve, and as it is rotated it becomes less obstructive to the air flow, allowing more air to pass through the valve. It can also be turned such that the motor would spin in reverse.
- The switch on the back plate uses a spring inside a pin to create compression so that once the pin enters one of the grooves designated for specific pressures, it locks into place until the user applies force to move it to another setting.
| Part | Assumptions | Equations | Explanation |
|---|---|---|---|
|
Plunger |
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Ideal Gas Law: PV=nRT (1) where P is the pressure, V is the volume, n is the moles of gas, R is the gas constant and T is the temperature Pressure Defined: P=F/A (2) where F is the normal force per unit area A, or the force applied perpendicular to the surface |
After the trigger is engaged and air is allowed to flow through, the plunger alters the volume of the container through which the air may flow. Given all of the assumptions, PV = constant. Therefore, an increase in volume given by the plunger would yield a decrease in pressure proportional to the increase in volume and vice versa.
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Back Plate and Switch |
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Hooke’s Law: F= -kx (3) where F is the force applied by the spring, k is the spring constant which is characteristic of the spring and x is the displacement of the spring |
The action of the spring pin locking into place in the grooves is defined by Hooke’s Law. |
Mechanism: Rotor and Fins
The rotor and fins act together as an impulse turbine to alter the pneumatic, stored energy to rotational energy via impulse, which it uses to spin the hammer.
- The fins serve as a point of impact for the compressed air flowing into the housing. The direction of the flowing air is changed, thus creating an impulse, or change in momentum that is transferred to the fins, causing the rotor to spin.
- The rotor is connected to the hammer and spins due to the force exerted by the compressed air on the fins. The spinning completes the conversion of the potential energy of the compressed air into mechanical energy and finally the torque output.
| Part | Assumptions | Equations | Explanation |
|---|---|---|---|
|
Fins |
|
Pressure Defined: PA=F (2)
J=∫Fdt = ∆p = m∆v (6a) where J is an impulse, ∫_∆tFdt is the integral of the force F over an interval of time t, ∆p is the change in momentum, m is the mass, and ∆v is the change in velocity |
The force exerted on the fins by the compressed air is a function of the pressure of the compressed air and the surface area of the fins. There is a direct relationship between the surface area of the fins and the force on the fins, and there is also a direct relationship between the pressure created by the air and the force exerted on the fins.
When air enters the rotor chamber it incurs a change in momentum caused by the contact with the initially stationary surface of the fins. This change in momentum is transferred to the fins as an impulse, which causes an increase in velocity of the fins and thus the rotation of the rotor. |
|
Rotor |
|
Newton’s Second Law: F=dp/dt=d(mv)/dt=m dv/dt=ma (6b) where F is the force, and dp/dt is the rate of change of its linear momentum (p) with respect to time (t) and d(mv)/dt, the rate of change of the mass (m) times the velocity (v) with respect to time; m is brought out as a constant under the assumption of constant mass and dv/dt becomes acceleration, a Torque as the Time Derivative of Angular Momentum: τ=dL/dt=dr/dt×p+r×dp/dt=r×F (7) where τ is torque, dL/dt is the rate of change of angular momentum with respect to time, dr/dt is the rate of change of the position vector (r) of the point relative to the center, and × indicates a cross product |
The force of the fins against the surface of the grooves in the rotor causes the rotor to accelerate.
Due to the conservation of linear momentum, the linear momentum of the fins created by the impulse from the contact with the compressed air is transferred to the rotor at points of distance r from the rotor’s central axis. The change in linear momentum at these points on the rotor’s grooves, now a change in angular momentum given the cylindrical shape of the rotor, then creates torque. The torque spins the rotor which, in turn, spins the hammer. |
Mechanism: Trigger
The trigger is a central part of the interface between the user and the control mechanisms of the impact wrench. It is the control mechanism that serves as a signal to allow air to flow into the device.
- The trigger is engaged by the user when the user applies pressure perpendicular to the surface of the trigger.
- The force exerted by the user on the trigger overcomes a spring mechanism in order to cause the shaft attached to the trigger to push the tipper valve to a position which allows for air to flow into the wrench. When the user releases the trigger, the spring forces the trigger back into place, thus disengaging the shaft from the tipper valve and allowing the tipper valve to close, no longer allowing air to flow into the device.